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-x^2+2.25x+2.25=0
We add all the numbers together, and all the variables
-1x^2+2.25x+2.25=0
a = -1; b = 2.25; c = +2.25;
Δ = b2-4ac
Δ = 2.252-4·(-1)·2.25
Δ = 14.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.25)-\sqrt{14.0625}}{2*-1}=\frac{-2.25-\sqrt{14.0625}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.25)+\sqrt{14.0625}}{2*-1}=\frac{-2.25+\sqrt{14.0625}}{-2} $
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